137=4(-4b+1)-3b

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Solution for 137=4(-4b+1)-3b equation: 



137=4(-4b+1)-3b

We move all terms to the left:

137-(4(-4b+1)-3b)=0



We calculate terms in parentheses: -(4(-4b+1)-3b), so:

4(-4b+1)-3b

We add all the numbers together, and all the variables

-3b+4(-4b+1)

We multiply parentheses

-3b-16b+4

We add all the numbers together, and all the variables

-19b+4

Back to the equation:

-(-19b+4)



We get rid of parentheses

19b-4+137=0

We add all the numbers together, and all the variables

19b+133=0

We move all terms containing b to the left, all other terms to the right

19b=-133

b=-133/19

b=-7

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