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11x(x+7)=146
We move all terms to the left:
11x(x+7)-(146)=0
We multiply parentheses
11x^2+77x-146=0
a = 11; b = 77; c = -146;
Δ = b2-4ac
Δ = 772-4·11·(-146)
Δ = 12353
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(77)-\sqrt{12353}}{2*11}=\frac{-77-\sqrt{12353}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(77)+\sqrt{12353}}{2*11}=\frac{-77+\sqrt{12353}}{22} $
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