5x(4-2x)=0

Solution for 5x(4-2x)=0 equation:

5x(4-2x)=0

We add all the numbers together, and all the variables

5x(-2x+4)=0

We multiply parentheses

-10x^2+20x=0

a = -10; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-10)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-10}=\frac{-40}{-20}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-10}=\frac{0}{-20}
=0
$