132=(15-2x)(10-2x)

Solution for 132=(15-2x)(10-2x) equation:

132=(15-2x)(10-2x)

We move all terms to the left:

132-((15-2x)(10-2x))=0

We add all the numbers together, and all the variables

-((-2x+15)(-2x+10))+132=0

We multiply parentheses ..

-((+4x^2-20x-30x+150))+132=0


We calculate terms in parentheses: -((+4x^2-20x-30x+150)), so:

(+4x^2-20x-30x+150)

We get rid of parentheses

4x^2-20x-30x+150

We add all the numbers together, and all the variables

4x^2-50x+150

Back to the equation:

-(4x^2-50x+150)


We get rid of parentheses

-4x^2+50x-150+132=0

We add all the numbers together, and all the variables

-4x^2+50x-18=0

a = -4; b = 50; c = -18;
Δ = b2-4ac
Δ = 502-4·(-4)·(-18)
Δ = 2212
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2212}=\sqrt{4*553}=\sqrt{4}*\sqrt{553}=2\sqrt{553}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{553}}{2*-4}=\frac{-50-2\sqrt{553}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{553}}{2*-4}=\frac{-50+2\sqrt{553}}{-8}
$