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(2x+12)/3x=5/6
We move all terms to the left:
(2x+12)/3x-(5/6)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
(2x+12)/3x-(+5/6)=0
We get rid of parentheses
(2x+12)/3x-5/6=0
We calculate fractions
(12x+72)/18x+(-15x)/18x=0
We multiply all the terms by the denominator
(12x+72)+(-15x)=0
We get rid of parentheses
12x-15x+72=0
We add all the numbers together, and all the variables
-3x+72=0
We move all terms containing x to the left, all other terms to the right
-3x=-72
x=-72/-3
x=+24
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