13-m=(-4+m)/2

Solution for 13-m=(-4+m)/2 equation:

13-m=(-4+m)/2

We move all terms to the left:

13-m-((-4+m)/2)=0

We add all the numbers together, and all the variables

-m-((m-4)/2)+13=0

We add all the numbers together, and all the variables

-1m-((m-4)/2)+13=0

We multiply all the terms by the denominator


-1m*2)-((m-4)+13*2)=0

We add all the numbers together, and all the variables

-1m*2)-((m-4)=0

Wy multiply elements

-2m^2=0

a = -2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-2)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$m=\frac{-b}{2a}=\frac{0}{-4}=0$