22=(x+1)+x

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Solution for 22=(x+1)+x equation: 



22=(x+1)+x

We move all terms to the left:

22-((x+1)+x)=0



We calculate terms in parentheses: -((x+1)+x), so:

(x+1)+x

We add all the numbers together, and all the variables

x+(x+1)

We get rid of parentheses

x+x+1

We add all the numbers together, and all the variables

2x+1

Back to the equation:

-(2x+1)



We get rid of parentheses

-2x-1+22=0

We add all the numbers together, and all the variables

-2x+21=0

We move all terms containing x to the left, all other terms to the right

-2x=-21

x=-21/-2

x=10+1/2

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