-1(1y-4)+3y=4(1y+10

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Solution for -1(1y-4)+3y=4(1y+10 equation: 



-1(1y-4)+3y=4(1y+10

We move all terms to the left:

-1(1y-4)+3y-(4(1y+10)=0

We add all the numbers together, and all the variables

-1(y-4)+3y-(4(y+10)=0

We add all the numbers together, and all the variables

3y-1(y-4)-(4(y+10)=0



We calculate terms in parentheses: -(4(y+10), so:

4(y+10





We calculate terms in parentheses: -(4(y+10), so:

4(y+10





We calculate terms in parentheses: -(4(y+10), so:

4(y+10





We calculate terms in parentheses: -(4(y+10), so:

4(y+10





We calculate terms in parentheses: -(4(y+10), so:

4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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4(y+10





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