13+6+(2x-18)=(4x-29)

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Solution for 13+6+(2x-18)=(4x-29) equation: 



13+6+(2x-18)=(4x-29)

We move all terms to the left:

13+6+(2x-18)-((4x-29))=0

We add all the numbers together, and all the variables

(2x-18)-((4x-29))+19=0

We get rid of parentheses

2x-((4x-29))-18+19=0



We calculate terms in parentheses: -((4x-29)), so:

(4x-29)

We get rid of parentheses

4x-29

Back to the equation:

-(4x-29)



We add all the numbers together, and all the variables

2x-(4x-29)+1=0

We get rid of parentheses

2x-4x+29+1=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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