-1/2(4x+10)=1/3(6-3x)

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Solution for -1/2(4x+10)=1/3(6-3x) equation: 



-1/2(4x+10)=1/3(6-3x)

We move all terms to the left:

-1/2(4x+10)-(1/3(6-3x))=0



Domain of the equation: 2(4x+10)!=0

x∈R





Domain of the equation: 3(6-3x))!=0

x∈R



We add all the numbers together, and all the variables

-1/2(4x+10)-(1/3(-3x+6))=0

We calculate fractions


(-3x(-)/(2(4x+10)*3(-3x+6)))+(-2x4/(2(4x+10)*3(-3x+6)))=0



We calculate terms in parentheses: +(-3x(-)/(2(4x+10)*3(-3x+6))), so:

-3x(-)/(2(4x+10)*3(-3x+6))

We add all the numbers together, and all the variables

-3x0/(2(4x+10)*3(-3x+6))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)





We calculate terms in parentheses: +(-2x4/(2(4x+10)*3(-3x+6))), so:

-2x4/(2(4x+10)*3(-3x+6))

We multiply all the terms by the denominator


-2x4

We add all the numbers together, and all the variables

-2x^4

We do not support expression: x^4

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