6(x+5)=8(2x-5)+20

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Solution for 6(x+5)=8(2x-5)+20 equation: 



6(x+5)=8(2x-5)+20

We move all terms to the left:

6(x+5)-(8(2x-5)+20)=0

We multiply parentheses

6x-(8(2x-5)+20)+30=0



We calculate terms in parentheses: -(8(2x-5)+20), so:

8(2x-5)+20

We multiply parentheses

16x-40+20

We add all the numbers together, and all the variables

16x-20

Back to the equation:

-(16x-20)



We get rid of parentheses

6x-16x+20+30=0

We add all the numbers together, and all the variables

-10x+50=0

We move all terms containing x to the left, all other terms to the right

-10x=-50

x=-50/-10

x=+5

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