13(x-4)=7(5x+8)

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Solution for 13(x-4)=7(5x+8) equation: 



13(x-4)=7(5x+8)

We move all terms to the left:

13(x-4)-(7(5x+8))=0

We multiply parentheses

13x-(7(5x+8))-52=0



We calculate terms in parentheses: -(7(5x+8)), so:

7(5x+8)

We multiply parentheses

35x+56

Back to the equation:

-(35x+56)



We get rid of parentheses

13x-35x-56-52=0

We add all the numbers together, and all the variables

-22x-108=0

We move all terms containing x to the left, all other terms to the right

-22x=108

x=108/-22

x=-4+10/11

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