13(b+4)=40-2(b-7)

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Solution for 13(b+4)=40-2(b-7) equation: 



13(b+4)=40-2(b-7)

We move all terms to the left:

13(b+4)-(40-2(b-7))=0

We multiply parentheses

13b-(40-2(b-7))+52=0



We calculate terms in parentheses: -(40-2(b-7)), so:

40-2(b-7)

determiningTheFunctionDomain
-2(b-7)+40

We multiply parentheses

-2b+14+40

We add all the numbers together, and all the variables

-2b+54

Back to the equation:

-(-2b+54)



We get rid of parentheses

13b+2b-54+52=0

We add all the numbers together, and all the variables

15b-2=0

We move all terms containing b to the left, all other terms to the right

15b=2

b=2/15

b=2/15

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