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2/5h=12
We move all terms to the left:
2/5h-(12)=0
Domain of the equation: 5h!=0We multiply all the terms by the denominator
h!=0/5
h!=0
h∈R
-12*5h+2=0
Wy multiply elements
-60h+2=0
We move all terms containing h to the left, all other terms to the right
-60h=-2
h=-2/-60
h=1/30
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