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5/2y=8/3y-24
We move all terms to the left:
5/2y-(8/3y-24)=0
Domain of the equation: 2y!=0
y!=0/2
y!=0
y∈R
Domain of the equation: 3y-24)!=0We get rid of parentheses
y∈R
5/2y-8/3y+24=0
We calculate fractions
15y/6y^2+(-16y)/6y^2+24=0
We multiply all the terms by the denominator
15y+(-16y)+24*6y^2=0
Wy multiply elements
144y^2+15y+(-16y)=0
We get rid of parentheses
144y^2+15y-16y=0
We add all the numbers together, and all the variables
144y^2-1y=0
a = 144; b = -1; c = 0;
Δ = b2-4ac
Δ = -12-4·144·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-1}{2*144}=\frac{0}{288} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+1}{2*144}=\frac{2}{288} =1/144 $
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