13(2b+9)=23(b+92)

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Solution for 13(2b+9)=23(b+92) equation: 



13(2b+9)=23(b+92)

We move all terms to the left:

13(2b+9)-(23(b+92))=0

We multiply parentheses

26b-(23(b+92))+117=0



We calculate terms in parentheses: -(23(b+92)), so:

23(b+92)

We multiply parentheses

23b+2116

Back to the equation:

-(23b+2116)



We get rid of parentheses

26b-23b-2116+117=0

We add all the numbers together, and all the variables

3b-1999=0

We move all terms containing b to the left, all other terms to the right

3b=1999

b=1999/3

b=666+1/3

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