8(2r-3)-r=3(3r+20)

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Solution for 8(2r-3)-r=3(3r+20) equation:



8(2r-3)-r=3(3r+20)
We move all terms to the left:
8(2r-3)-r-(3(3r+20))=0
We add all the numbers together, and all the variables
-1r+8(2r-3)-(3(3r+20))=0
We multiply parentheses
-1r+16r-(3(3r+20))-24=0
We calculate terms in parentheses: -(3(3r+20)), so:
3(3r+20)
We multiply parentheses
9r+60
Back to the equation:
-(9r+60)
We add all the numbers together, and all the variables
15r-(9r+60)-24=0
We get rid of parentheses
15r-9r-60-24=0
We add all the numbers together, and all the variables
6r-84=0
We move all terms containing r to the left, all other terms to the right
6r=84
r=84/6
r=14

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