-4(v+3)=6v-2+2(2v+3)

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Solution for -4(v+3)=6v-2+2(2v+3) equation: 



-4(v+3)=6v-2+2(2v+3)

We move all terms to the left:

-4(v+3)-(6v-2+2(2v+3))=0

We multiply parentheses

-4v-(6v-2+2(2v+3))-12=0



We calculate terms in parentheses: -(6v-2+2(2v+3)), so:

6v-2+2(2v+3)

determiningTheFunctionDomain
6v+2(2v+3)-2

We multiply parentheses

6v+4v+6-2

We add all the numbers together, and all the variables

10v+4

Back to the equation:

-(10v+4)



We get rid of parentheses

-4v-10v-4-12=0

We add all the numbers together, and all the variables

-14v-16=0

We move all terms containing v to the left, all other terms to the right

-14v=16

v=16/-14

v=-1+1/7

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