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12y-3(y-3)=6y+8-y+2
We move all terms to the left:
12y-3(y-3)-(6y+8-y+2)=0
We add all the numbers together, and all the variables
12y-3(y-3)-(5y+10)=0
We multiply parentheses
12y-3y-(5y+10)+9=0
We get rid of parentheses
12y-3y-5y-10+9=0
We add all the numbers together, and all the variables
4y-1=0
We move all terms containing y to the left, all other terms to the right
4y=1
y=1/4
y=1/4
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