3*(x+2)=2(17-2x)

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Solution for 3*(x+2)=2(17-2x) equation: 



3(x+2)=2(17-2x)

We move all terms to the left:

3(x+2)-(2(17-2x))=0

We add all the numbers together, and all the variables

3(x+2)-(2(-2x+17))=0

We multiply parentheses

3x-(2(-2x+17))+6=0



We calculate terms in parentheses: -(2(-2x+17)), so:

2(-2x+17)

We multiply parentheses

-4x+34

Back to the equation:

-(-4x+34)



We get rid of parentheses

3x+4x-34+6=0

We add all the numbers together, and all the variables

7x-28=0

We move all terms containing x to the left, all other terms to the right

7x=28

x=28/7

x=4

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