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(2x-15)/7=x+5
We move all terms to the left:
(2x-15)/7-(x+5)=0
We get rid of parentheses
(2x-15)/7-x-5=0
We multiply all the terms by the denominator
(2x-15)-x*7-5*7=0
We add all the numbers together, and all the variables
(2x-15)-x*7-35=0
Wy multiply elements
(2x-15)-7x-35=0
We get rid of parentheses
2x-7x-15-35=0
We add all the numbers together, and all the variables
-5x-50=0
We move all terms containing x to the left, all other terms to the right
-5x=50
x=50/-5
x=-10
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