12x2-35x+18=0

Solution for 12x2-35x+18=0 equation:

12x^2-35x+18=0

a = 12; b = -35; c = +18;
Δ = b2-4ac
Δ = -352-4·12·18
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-19}{2*12}=\frac{16}{24}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+19}{2*12}=\frac{54}{24}
=2+1/4
$