6-(3+2x)=3x+(2x-4)

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Solution for 6-(3+2x)=3x+(2x-4) equation: 



6-(3+2x)=3x+(2x-4)

We move all terms to the left:

6-(3+2x)-(3x+(2x-4))=0

We add all the numbers together, and all the variables

-(2x+3)-(3x+(2x-4))+6=0

We get rid of parentheses

-2x-(3x+(2x-4))-3+6=0



We calculate terms in parentheses: -(3x+(2x-4)), so:

3x+(2x-4)

We get rid of parentheses

3x+2x-4

We add all the numbers together, and all the variables

5x-4

Back to the equation:

-(5x-4)



We add all the numbers together, and all the variables

-2x-(5x-4)+3=0

We get rid of parentheses

-2x-5x+4+3=0

We add all the numbers together, and all the variables

-7x+7=0

We move all terms containing x to the left, all other terms to the right

-7x=-7

x=-7/-7

x=1

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