12x2+26x+12=0

Solution for 12x2+26x+12=0 equation:

12x^2+26x+12=0

a = 12; b = 26; c = +12;
Δ = b2-4ac
Δ = 262-4·12·12
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-10}{2*12}=\frac{-36}{24}
=-1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+10}{2*12}=\frac{-16}{24}
=-2/3
$