3p+1p(1-p)=4p+2(1-p)

Solution for 3p+1p(1-p)=4p+2(1-p) equation:

3p+1p(1-p)=4p+2(1-p)

We move all terms to the left:

3p+1p(1-p)-(4p+2(1-p))=0

We add all the numbers together, and all the variables

3p+1p(-1p+1)-(4p+2(-1p+1))=0

We multiply parentheses

-1p^2+3p+p-(4p+2(-1p+1))=0


We calculate terms in parentheses: -(4p+2(-1p+1)), so:

4p+2(-1p+1)

We multiply parentheses

4p-2p+2

We add all the numbers together, and all the variables

2p+2

Back to the equation:

-(2p+2)


We add all the numbers together, and all the variables

-1p^2+4p-(2p+2)=0

We get rid of parentheses

-1p^2+4p-2p-2=0

We add all the numbers together, and all the variables

-1p^2+2p-2=0

a = -1; b = 2; c = -2;
Δ = b2-4ac
Δ = 22-4·(-1)·(-2)
Δ = -4
Delta is less than zero, so there is no solution for the equation