3(3f-7)=2(4f+3)

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Solution for 3(3f-7)=2(4f+3) equation: 



3(3f-7)=2(4f+3)

We move all terms to the left:

3(3f-7)-(2(4f+3))=0

We multiply parentheses

9f-(2(4f+3))-21=0



We calculate terms in parentheses: -(2(4f+3)), so:

2(4f+3)

We multiply parentheses

8f+6

Back to the equation:

-(8f+6)



We get rid of parentheses

9f-8f-6-21=0

We add all the numbers together, and all the variables

f-27=0

We move all terms containing f to the left, all other terms to the right

f=27

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