12t-(4t+10)=1/4(16+32t)

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Solution for 12t-(4t+10)=1/4(16+32t) equation: 



12t-(4t+10)=1/4(16+32t)

We move all terms to the left:

12t-(4t+10)-(1/4(16+32t))=0



Domain of the equation: 4(16+32t))!=0

t∈R



We add all the numbers together, and all the variables

12t-(4t+10)-(1/4(32t+16))=0

We get rid of parentheses

12t-4t-(1/4(32t+16))-10=0

We multiply all the terms by the denominator


12t*4(32t+16))-4t*4(32t+16))-(1-10*4(32t+16))=0

We add all the numbers together, and all the variables

12t*4(32t+16))-4t*4(32t+16))-(1-10*4(32t=0

Wy multiply elements

192t^3(3+16))-(1-10*4(32t=0

We do not support etpression: t^3(3

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