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-1/2x+3=5x+25
We move all terms to the left:
-1/2x+3-(5x+25)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
-1/2x-5x-25+3=0
We multiply all the terms by the denominator
-5x*2x-25*2x+3*2x-1=0
Wy multiply elements
-10x^2-50x+6x-1=0
We add all the numbers together, and all the variables
-10x^2-44x-1=0
a = -10; b = -44; c = -1;
Δ = b2-4ac
Δ = -442-4·(-10)·(-1)
Δ = 1896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1896}=\sqrt{4*474}=\sqrt{4}*\sqrt{474}=2\sqrt{474}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-2\sqrt{474}}{2*-10}=\frac{44-2\sqrt{474}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+2\sqrt{474}}{2*-10}=\frac{44+2\sqrt{474}}{-20} $
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