(-(2/7)x)+6+(1/7)x=18

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Solution for (-(2/7)x)+6+(1/7)x=18 equation: 



(-(2/7)x)+6+(1/7)x=18

We move all terms to the left:

(-(2/7)x)+6+(1/7)x-(18)=0



Domain of the equation: 7)x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 7)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(-(+2/7)x)+(+1/7)x+6-18=0

We add all the numbers together, and all the variables

(-(+2/7)x)+(+1/7)x-12=0

We multiply parentheses

x^2+(-(+2/7)x)-12=0

We multiply all the terms by the denominator


x^2*7)x)+(-(-12*7)x)+2=0

We add all the numbers together, and all the variables

x^2*7)x)+(-(-84)x)+2=0

Wy multiply elements

7x^3-84)x)+2=0

We do not support expression: x^3

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