12=7+(4/3+z)

Solution for 12=7+(4/3+z) equation:

12=7+(4/3+z)

We move all terms to the left:

12-(7+(4/3+z))=0


Domain of the equation: 3+z))!=0

We move all terms containing z to the left, all other terms to the right

z))!=-3

z!=-3/1

z!=-3

z∈R


We add all the numbers together, and all the variables

-(7+(+z+4/3))+12=0

We multiply all the terms by the denominator


-(7+(+z+4+12*3))=0


We calculate terms in parentheses: -(7+(+z+4+12*3)), so:

7+(+z+4+12*3)

determiningTheFunctionDomain
(+z+4+12*3)+7

We add all the numbers together, and all the variables

(z+40)+7

We get rid of parentheses

z+40+7

We add all the numbers together, and all the variables

z+47

Back to the equation:

-(z+47)


We get rid of parentheses

-z-47=0

We add all the numbers together, and all the variables

-1z-47=0

We move all terms containing z to the left, all other terms to the right

-z=47

z=47/-1

z=-47