(x-2)-2(x+1)=x+1-(x-5)

Solution for (x-2)-2(x+1)=x+1-(x-5) equation:

(x-2)-2(x+1)=x+1-(x-5)

We move all terms to the left:

(x-2)-2(x+1)-(x+1-(x-5))=0

We multiply parentheses

(x-2)-2x-(x+1-(x-5))-2=0

We get rid of parentheses

x-2x-(x+1-(x-5))-2-2=0


We calculate terms in parentheses: -(x+1-(x-5)), so:

x+1-(x-5)

determiningTheFunctionDomain
x-(x-5)+1

We get rid of parentheses

x-x+5+1

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)


We add all the numbers together, and all the variables

-1x-10=0

We move all terms containing x to the left, all other terms to the right

-x=10

x=10/-1

x=-10