12=7+(4/(3+z))

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Solution for 12=7+(4/(3+z)) equation:



12=7+(4/(3+z))
We move all terms to the left:
12-(7+(4/(3+z)))=0
Domain of the equation: (3+z)))!=0
We move all terms containing z to the left, all other terms to the right
z))!=-3
z!=-3/1
z!=-3
z∈R
We add all the numbers together, and all the variables
-(7+(4/(z+3)))+12=0
We multiply all the terms by the denominator
-(7+(4+12*(z+3)))=0
We calculate terms in parentheses: -(7+(4+12*(z+3))), so:
7+(4+12*(z+3))
determiningTheFunctionDomain (4+12*(z+3))+7
We calculate terms in parentheses: +(4+12*(z+3)), so:
4+12*(z+3)
determiningTheFunctionDomain 12*(z+3)+4
We multiply parentheses
12z+36+4
We add all the numbers together, and all the variables
12z+40
Back to the equation:
+(12z+40)
We get rid of parentheses
12z+40+7
We add all the numbers together, and all the variables
12z+47
Back to the equation:
-(12z+47)
We get rid of parentheses
-12z-47=0
We move all terms containing z to the left, all other terms to the right
-12z=47
z=47/-12
z=-3+11/12

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