128=2(x+8)2(x)

Solution for 128=2(x+8)2(x) equation:

128=2(x+8)2(x)

We move all terms to the left:

128-(2(x+8)2(x))=0


We calculate terms in parentheses: -(2(x+8)2x), so:

2(x+8)2x

We multiply parentheses

4x^2+32x

Back to the equation:

-(4x^2+32x)


We get rid of parentheses

-4x^2-32x+128=0

a = -4; b = -32; c = +128;
Δ = b2-4ac
Δ = -322-4·(-4)·128
Δ = 3072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3072}=\sqrt{1024*3}=\sqrt{1024}*\sqrt{3}=32\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32\sqrt{3}}{2*-4}=\frac{32-32\sqrt{3}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32\sqrt{3}}{2*-4}=\frac{32+32\sqrt{3}}{-8}
$