4(b+5)/3=(3b-35)/6

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Solution for 4(b+5)/3=(3b-35)/6 equation: 



4(b+5)/3=(3b-35)/6

We move all terms to the left:

4(b+5)/3-((3b-35)/6)=0

We calculate fractions


4b/()+(-((3b-35)*3)/()=0



We calculate terms in parentheses: +(-((3b-35)*3)/(), so:

-((3b-35)*3)/(

We multiply all the terms by the denominator


-((3b-35)*3)



We calculate terms in parentheses: -((3b-35)*3), so:

(3b-35)*3

We multiply parentheses

9b-105

Back to the equation:

-(9b-105)



We get rid of parentheses

-9b+105

Back to the equation:

+(-9b+105)



We get rid of parentheses

4b/()-9b+105=0

We multiply all the terms by the denominator


4b-9b*()+105*()=0

We add all the numbers together, and all the variables

4b-9b*()=0

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