128=2(w+1)+2w

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Solution for 128=2(w+1)+2w equation: 



128=2(w+1)+2w

We move all terms to the left:

128-(2(w+1)+2w)=0



We calculate terms in parentheses: -(2(w+1)+2w), so:

2(w+1)+2w

We add all the numbers together, and all the variables

2w+2(w+1)

We multiply parentheses

2w+2w+2

We add all the numbers together, and all the variables

4w+2

Back to the equation:

-(4w+2)



We get rid of parentheses

-4w-2+128=0

We add all the numbers together, and all the variables

-4w+126=0

We move all terms containing w to the left, all other terms to the right

-4w=-126

w=-126/-4

w=31+1/2

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