5(2c+5)-5c=2(3c+2)+11

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Solution for 5(2c+5)-5c=2(3c+2)+11 equation: 



5(2c+5)-5c=2(3c+2)+11

We move all terms to the left:

5(2c+5)-5c-(2(3c+2)+11)=0

We add all the numbers together, and all the variables

-5c+5(2c+5)-(2(3c+2)+11)=0

We multiply parentheses

-5c+10c-(2(3c+2)+11)+25=0



We calculate terms in parentheses: -(2(3c+2)+11), so:

2(3c+2)+11

We multiply parentheses

6c+4+11

We add all the numbers together, and all the variables

6c+15

Back to the equation:

-(6c+15)



We add all the numbers together, and all the variables

5c-(6c+15)+25=0

We get rid of parentheses

5c-6c-15+25=0

We add all the numbers together, and all the variables

-1c+10=0

We move all terms containing c to the left, all other terms to the right

-c=-10

c=-10/-1

c=+10

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