128-18x2=0

Solution for 128-18x2=0 equation:

128-18x^2=0

a = -18; b = 0; c = +128;
Δ = b2-4ac
Δ = 02-4·(-18)·128
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*-18}=\frac{-96}{-36}
=2+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*-18}=\frac{96}{-36}
=-2+2/3
$