9(n+1)=2(n-2)

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Solution for 9(n+1)=2(n-2) equation: 



9(n+1)=2(n-2)

We move all terms to the left:

9(n+1)-(2(n-2))=0

We multiply parentheses

9n-(2(n-2))+9=0



We calculate terms in parentheses: -(2(n-2)), so:

2(n-2)

We multiply parentheses

2n-4

Back to the equation:

-(2n-4)



We get rid of parentheses

9n-2n+4+9=0

We add all the numbers together, and all the variables

7n+13=0

We move all terms containing n to the left, all other terms to the right

7n=-13

n=-13/7

n=-1+6/7

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