-29=3(-8+2c)-7c

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Solution for -29=3(-8+2c)-7c equation: 



-29=3(-8+2c)-7c

We move all terms to the left:

-29-(3(-8+2c)-7c)=0

We add all the numbers together, and all the variables

-(3(2c-8)-7c)-29=0



We calculate terms in parentheses: -(3(2c-8)-7c), so:

3(2c-8)-7c

We add all the numbers together, and all the variables

-7c+3(2c-8)

We multiply parentheses

-7c+6c-24

We add all the numbers together, and all the variables

-1c-24

Back to the equation:

-(-1c-24)



We get rid of parentheses

1c+24-29=0

We add all the numbers together, and all the variables

c-5=0

We move all terms containing c to the left, all other terms to the right

c=5

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