12-2(x-1)-4(x+1)=3-2(x+1)

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Solution for 12-2(x-1)-4(x+1)=3-2(x+1) equation: 



12-2(x-1)-4(x+1)=3-2(x+1)

We move all terms to the left:

12-2(x-1)-4(x+1)-(3-2(x+1))=0

We multiply parentheses

-2x-4x-(3-2(x+1))+2-4+12=0



We calculate terms in parentheses: -(3-2(x+1)), so:

3-2(x+1)

determiningTheFunctionDomain
-2(x+1)+3

We multiply parentheses

-2x-2+3

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We add all the numbers together, and all the variables

-6x-(-2x+1)+10=0

We get rid of parentheses

-6x+2x-1+10=0

We add all the numbers together, and all the variables

-4x+9=0

We move all terms containing x to the left, all other terms to the right

-4x=-9

x=-9/-4

x=2+1/4

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