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6(2x-3)=8-2(3x+1)
We move all terms to the left:
6(2x-3)-(8-2(3x+1))=0
We multiply parentheses
12x-(8-2(3x+1))-18=0
We calculate terms in parentheses: -(8-2(3x+1)), so:We get rid of parentheses
8-2(3x+1)
determiningTheFunctionDomain -2(3x+1)+8
We multiply parentheses
-6x-2+8
We add all the numbers together, and all the variables
-6x+6
Back to the equation:
-(-6x+6)
12x+6x-6-18=0
We add all the numbers together, and all the variables
18x-24=0
We move all terms containing x to the left, all other terms to the right
18x=24
x=24/18
x=1+1/3
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