4(x-2)+1+3x=5(x+3)

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Solution for 4(x-2)+1+3x=5(x+3) equation: 



4(x-2)+1+3x=5(x+3)

We move all terms to the left:

4(x-2)+1+3x-(5(x+3))=0

We add all the numbers together, and all the variables

3x+4(x-2)-(5(x+3))+1=0

We multiply parentheses

3x+4x-(5(x+3))-8+1=0



We calculate terms in parentheses: -(5(x+3)), so:

5(x+3)

We multiply parentheses

5x+15

Back to the equation:

-(5x+15)



We add all the numbers together, and all the variables

7x-(5x+15)-7=0

We get rid of parentheses

7x-5x-15-7=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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