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12+2/3b=10
We move all terms to the left:
12+2/3b-(10)=0
Domain of the equation: 3b!=0We add all the numbers together, and all the variables
b!=0/3
b!=0
b∈R
2/3b+2=0
We multiply all the terms by the denominator
2*3b+2=0
Wy multiply elements
6b+2=0
We move all terms containing b to the left, all other terms to the right
6b=-2
b=-2/6
b=-1/3
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