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2.5x-(1.1x-2)=2x(0.7x)
We move all terms to the left:
2.5x-(1.1x-2)-(2x(0.7x))=0
We add all the numbers together, and all the variables
2.5x-(1.1x-2)-(2x(+0.7x))=0
We get rid of parentheses
2.5x-1.1x-(2x(+0.7x))+2=0
We calculate terms in parentheses: -(2x(+0.7x)), so:determiningTheFunctionDomain -x^2+2.5x-1.1x+2=0
2x(+0.7x)
We multiply parentheses
0x^2
We add all the numbers together, and all the variables
x^2
Back to the equation:
-(x^2)
We add all the numbers together, and all the variables
-1x^2+1.4x+2=0
a = -1; b = 1.4; c = +2;
Δ = b2-4ac
Δ = 1.42-4·(-1)·2
Δ = 9.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.4)-\sqrt{9.96}}{2*-1}=\frac{-1.4-\sqrt{9.96}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.4)+\sqrt{9.96}}{2*-1}=\frac{-1.4+\sqrt{9.96}}{-2} $
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