(3x-1)(x+1)=(3x)(3x)

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Solution for (3x-1)(x+1)=(3x)(3x) equation: 



(3x-1)(x+1)=(3x)(3x)

We move all terms to the left:

(3x-1)(x+1)-((3x)(3x))=0

determiningTheFunctionDomain
(3x-1)(x+1)-3x3x=0

We multiply parentheses ..

(+3x^2+3x-1x-1)-3x3x=0

We get rid of parentheses

3x^2+3x-1x-3x3x-1=0

We add all the numbers together, and all the variables

3x^2+2x-3x3x-1=0

We move all terms containing x to the left, all other terms to the right

3x^2+2x-3x3x=1

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