12+12=3(y+2)

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Solution for 12+12=3(y+2) equation: 



12+12=3(y+2)

We move all terms to the left:

12+12-(3(y+2))=0

We add all the numbers together, and all the variables

-(3(y+2))+24=0



We calculate terms in parentheses: -(3(y+2)), so:

3(y+2)

We multiply parentheses

3y+6

Back to the equation:

-(3y+6)



We get rid of parentheses

-3y-6+24=0

We add all the numbers together, and all the variables

-3y+18=0

We move all terms containing y to the left, all other terms to the right

-3y=-18

y=-18/-3

y=+6

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