(10x+38)(18x-2)=180

Solution for (10x+38)(18x-2)=180 equation:

(10x+38)(18x-2)=180

We move all terms to the left:

(10x+38)(18x-2)-(180)=0

We multiply parentheses ..

(+180x^2-20x+684x-76)-180=0

We get rid of parentheses

180x^2-20x+684x-76-180=0

We add all the numbers together, and all the variables

180x^2+664x-256=0

a = 180; b = 664; c = -256;
Δ = b2-4ac
Δ = 6642-4·180·(-256)
Δ = 625216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{625216}=\sqrt{64*9769}=\sqrt{64}*\sqrt{9769}=8\sqrt{9769}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(664)-8\sqrt{9769}}{2*180}=\frac{-664-8\sqrt{9769}}{360}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(664)+8\sqrt{9769}}{2*180}=\frac{-664+8\sqrt{9769}}{360}
$