12(x-2)+3x=12(x+6)+2

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Solution for 12(x-2)+3x=12(x+6)+2 equation: 



12(x-2)+3x=12(x+6)+2

We move all terms to the left:

12(x-2)+3x-(12(x+6)+2)=0

We add all the numbers together, and all the variables

3x+12(x-2)-(12(x+6)+2)=0

We multiply parentheses

3x+12x-(12(x+6)+2)-24=0



We calculate terms in parentheses: -(12(x+6)+2), so:

12(x+6)+2

We multiply parentheses

12x+72+2

We add all the numbers together, and all the variables

12x+74

Back to the equation:

-(12x+74)



We add all the numbers together, and all the variables

15x-(12x+74)-24=0

We get rid of parentheses

15x-12x-74-24=0

We add all the numbers together, and all the variables

3x-98=0

We move all terms containing x to the left, all other terms to the right

3x=98

x=98/3

x=32+2/3

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