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(2x-5)(3x-22)=180
We move all terms to the left:
(2x-5)(3x-22)-(180)=0
We multiply parentheses ..
(+6x^2-44x-15x+110)-180=0
We get rid of parentheses
6x^2-44x-15x+110-180=0
We add all the numbers together, and all the variables
6x^2-59x-70=0
a = 6; b = -59; c = -70;
Δ = b2-4ac
Δ = -592-4·6·(-70)
Δ = 5161
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-\sqrt{5161}}{2*6}=\frac{59-\sqrt{5161}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+\sqrt{5161}}{2*6}=\frac{59+\sqrt{5161}}{12} $
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