4(2r-5)=6(3r+5)

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Solution for 4(2r-5)=6(3r+5) equation: 



4(2r-5)=6(3r+5)

We move all terms to the left:

4(2r-5)-(6(3r+5))=0

We multiply parentheses

8r-(6(3r+5))-20=0



We calculate terms in parentheses: -(6(3r+5)), so:

6(3r+5)

We multiply parentheses

18r+30

Back to the equation:

-(18r+30)



We get rid of parentheses

8r-18r-30-20=0

We add all the numbers together, and all the variables

-10r-50=0

We move all terms containing r to the left, all other terms to the right

-10r=50

r=50/-10

r=-5

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